x^2+5jx+4=y

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Solution for x^2+5jx+4=y equation:


Simplifying
x2 + 5jx + 4 = y

Reorder the terms:
4 + 5jx + x2 = y

Solving
4 + 5jx + x2 = y

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + 5jx + -4 + x2 = -4 + y

Reorder the terms:
4 + -4 + 5jx + x2 = -4 + y

Combine like terms: 4 + -4 = 0
0 + 5jx + x2 = -4 + y
5jx + x2 = -4 + y

Add '-1x2' to each side of the equation.
5jx + x2 + -1x2 = -4 + -1x2 + y

Combine like terms: x2 + -1x2 = 0
5jx + 0 = -4 + -1x2 + y
5jx = -4 + -1x2 + y

Divide each side by '5x'.
j = -0.8x-1 + -0.2x + 0.2x-1y

Simplifying
j = -0.8x-1 + -0.2x + 0.2x-1y

Reorder the terms:
j = -0.8x-1 + 0.2x-1y + -0.2x

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